MTE 484 Lab 2

$$\begin{array}{r}{K}_1=-2.1079\\ \tau =0.0197\end{array}$$

Motor equation:

$$\begin{array}{rl}\frac{\theta (s)}{V(s)}& =\frac{K_1}{s(\tau s+1)}\\ & =\frac{-2.1079}{s(0.0197s+1)}\\ & =\frac{-2.1079}{s}+\frac{0.04152563}{0.0197s+1}\end{array}$$

Pole at:

$$\begin{array}{rl}0.0197s+1& =0\\ s=-\frac{1}{0.0197}& =-50.76142132\end{array}$$

0.04152563